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Details

Using Substitution
Evaluating algebraic expressions using substitution
10
Mathematics
8th Grade
08/24/2010

Additional Mathematics Flashcards

 


 

Cards

Term

Let x = -4 and y = -5

 

-5x - 2y2

Definition

-5(-4) - 2(-5)2

20 - 2(25)

20 - 50

-30

Term

Let x = -2 and y = 5

 

-6x2y - -y2

Definition

-6(-2)2(5) - -(5)2

-6(4)(5) + 25

-120 + 25

-95

Term

Let x = -9 and y = -4

xy - 2(x - y)

Definition

-9(-4) - 2(-9 - -4)

36 - 2(-5)

36 + 10

46

Term

Let x = -3 and y = -5

 

x2y - x + y

Definition

(-3)2(-5) - -3 + -5

9(-5) + 3 - 5

-45 + 3 - 5

-47

Term

Let x = -10 and y = 2

 

x2y - y3x

Definition

(-10)2(2) - (2)3(-10)

(100)(2) - (8)(-10)

200 +80

280

Term

Let x = -5 and y = -6

 

(xy)2 - x

Definition

[(-5)(-6)]2 - (-5)

(30)2 + 5

900 + 5

905

Term

Let x = -4 and y = -3

 

5xy - 2(x + y)

Definition

5(-4)(-3) - 2(-4 + -3)

60 - 2(-7)

60 + 14

74

Term

Let x = -7 and y = 5

 

-2x - (x + y)(x - y)

Definition

-2(-7) - (-7 + 5)(-7 - 5)

14 - (-2)(-12)

14 - 24

-10

Term

Let x = -4 and y = 2

 

-5xy - (y - x)

Definition

-5(-4)(2) - (2 - -4)

80 - 6

74

Term

Let x = -5 and y = -6

 

-7xy - 2(x + y)

Definition

-7(-5)(-6) - 2(-5 + -6)

-210 - 2(-11)

-210 + 22

-188

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