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Equation for parabola f(x)= 2(x-4)+8 |
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F(x)= a(x-h) +k F(x)= 2(x-4)+8 (h=4, k=8 Vertex= (4,8) |
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equation oof parabola f(x)= 3x^2 -8x +4 |
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f(x)=ax^2+bx+c vertex= x= -b/2a y= F(-b/2a) 3x^2 -8x+4 -b=8 2a=2(3)=6 8/6=4/3 x=4/3 f(-b/2a)= f(4/3) 3(4/3)^2-8(4/3)+4= -4/3 y=-4/3 vertex= (4/3,-4/3) |
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opens up or down ----leading coeffient |
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non ngitive or raction integers |
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largest exponent ex. Ax^3+ Bx^7+Cx^4 degree =Bx^7 = 7 |
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leading coeffient test to determine end behavior |
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ax^even = rise rise -ax^even = fall, fall (f(x)=x^2or parabala) ax^odd = fall rise -ax^odd = fall rise (f(x)= x^3 or cubic) |
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f(x) = 0 (x-int) ex. f(x)=3(x+5)(x+2)^2 zero's= -5 with multplicity of 1 which is odd so it crosses at -5 and zeros at -2 with multiplicty of 2 which is even so it crosses at -2 |
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Rational equations f(x) = p(x)/q(x) |
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Den ≠ 0 Veritcal Asymptote |
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veritcle Symptote = -5 b/c x+5=0 x=-5 and the den cannot equal o so this is where the VA is. |
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n< m ------y=0 n=m ------ leading coeff/leading coeff n>m no HA |
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determine symetry for f(x)= p(x)/q(x) |
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f(x)=f(-x) y axis symetry f(x)= -f(x) origin symetry if some change but not all then not symetirc to y or origin |
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p(x)=o = X int [top = 0] q(x)=0 = V/A. [bottom =0] |
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1) set = to 0 on right 2) factor 3) get crit # 4) build sign chart with crit# as boundry pts 5) fill in test #s 6 determine correct interval (>0 means pos and <0 means neg) 7) write answer in interval notion (-∞,# )] U [(#,∞)] |
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