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solving for y (0,y)
solving for x (x,0) |
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testing an equation for symetry |
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symetry towards the:
x-axsis- relace y with -y
y-axsis- replace x with -x
origin- replace x and y with -x,-y
*if an equivilant equation results it is symetric to that axsis |
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point slope form equation |
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standard form of an equation of a circle |
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general form of an equation of a circle |
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if and only if there is no repeated x values, do the verticle line test |
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f(-x)= -f(x)
if and only if the graph is symetrical with respect to the origin |
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f(-x)= f(x)
if and only if the graph is symetrical with respect to the y-axsis |
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adverage rate of change for functions |
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a function is increasing when |
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a function is decreasing when |
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know the library of functions and their graphs |
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squared functions and its shifts about the graph |
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f(x)= x2-3 (left)
f(x)= x2+3 (right)
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absolute value functions and thier graphs |
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square root functions and their graphs |
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cubed functions and their graphs |
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finding the minimum or maximum values of a function |
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If a > 0 then the vertex (h; f(h)) is the minimum value for f(x) on the graph
If a < 0 then the vertex (h; f(h)) is the maximum value for f(x) on the graph |
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how to determine where the values of functions [f(x)] lie on a graph |
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The values for which f(x) 0 or f(x) < 0 fall beneath the x-axis
The value for which f(x) 0 or f(x) > 0 rest above the x-axis |
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what is a degree of a polynomial |
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the highest power of x present amongst all terms
within the polynomial |
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what are the power functions of degrees in a polynomial |
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degree n is of the form f(x) = axn where a 6= 0 is a real number
and n > 0 is an integer
The graph of odd powered functions are s-shaped in nature, becoming ever more angular as the power increases
The graph of even powered functions are parabolic in nature, becoming ever more angular as the power increases
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how do you figure out if a polynomial is going to open upwards or downwards |
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For an even function f(x) = axn, if a > 0, then the parabola opens upwards,
whereas if a < 0, then the parabola opens down.
For an odd function, if a > 0, then the s-shaped graph goes "uphill" in reading
direction, whereas if < 0, then the graph tends "downhill" in reading direction |
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how do you know if the graph of a polynomial is going to cut or pass through the axsis |
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For m odd, the graph cuts through the x-axis at x = r
For m even, the graph touches the x-axis at x = r
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how to determine the h/v asymptote of a polynomial |
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i. If m = n; then the horizontal asymptote of R(x) is the line y = an
bm
ii. If m > n; then the horizontal asymptote of R(x) is the line y = 0
ii. If m < n; there is no horizontal asymptote |
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graphing a rational function |
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If a vertical asymptote has even multiplicity, then the graph approaches the
asymptote in the same direction from both sides
If a vertical asymptote has odd multiplicity, then the graph approaches the
asymptote in opposite directions from both sides |
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you have to write the U if there is a zero in the denominator of an inequality |
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determining if a graph is a one to one fuction |
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We can think of a 1-1 function in the sense that for each y-value, there is a unique corresponding x-value, no repeating y values
use the horixontal line test |
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exponiental equation characteristics |
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An exponential function is of the form f(x) = ax, where a > 0 and a 6= 1
If 0 < a < 1, then the graph of f(x) = ax decreases in reading direction
If a > 1, then the graph of f(x) = ax increases in reading direction
i The points (a1; a-a); (a; 1); and (1; a) are on the graph of f(x)
ii There are no x-intercepts
iii the Horizontal Asymptote is the line y = 0 i.e. the x-axis
iv For 0 < a < 1, the graph is always decreasing and 1 - 1 (i.e. invertible)
For a > 1, the graph is always increasing and 1 - 1 (i.e. invertible)
v The domain is all real numbers; (∞1;1)
The range is all positive numbers; (0;1) |
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how to solve a logarithim |
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i loga 1 = 0 because a0 = 1 for all a > 0
ii loga a = 1 because a1 = a
iii aloga x = x because loga x is the exponent to which a must be raised to get x
iv loga ax = x because ax = ax
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i loga(MN) = logaM + loga N
ii loga(M
N ) = logaM |
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(x - h)2 = 4a(y - k) (h; k) (h; k + a) y = k - a opens up
(x - h)2 = -4a(y - k) (h; k) (h; k - a) y = k + a opens down
(y - k)2 = 4a(x - h) (h; k) (h + a; k) x = h - a opens right
(y - k)2= -4a(x - h) (h; k) (h - a; k) x = h + a opens left |
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a function whose domain is a subset of the positive integers,
denoted {an} |
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