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A complete set of all possible distinct outcomes and their probabilities of occurring – Sum of these probabilities = 1 |
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mean of the probability distribution (the “expected” value of the random variable x) |
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2 = variance of the probability distribution |
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Binomial Distribution 3 indicators |
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The binomial distribution has 3 essential properties: 1. Each elementary event is classified into one of two mutually exclusive and collectively exhaustive categories, such as success or failure. 2. The probability of success, p, is constant from trial to trial. Likewise, the probability of failure, 1- p, is constant from trial to trial. 3. The outcome (success or failure) on a particular trial is independent of the outcome on any other trial |
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Shape of the distribution: p = 0.5 |
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Shape of the distribution:p < 0.5 |
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Shape of the distribution:p > 0.5 |
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Hypergeometric Distribution |
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x (meaning that you have x number of successes in your sample), given knowledge of n, N, and A. |
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Hypergeometric Distributionn =n |
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Hypergeometric Distribution=N |
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Hypergeometric Distribution=x |
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number of successes in sample |
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Hypergeometric Distribution=A |
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number of successes in Population |
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Hypergeometric Distribution N-A |
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number of failures in population |
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Is hypergeometric with or without replacement? |
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Hypergeometric Distribution μ = |
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n * A / N (sample size divided by fraction of successes in the population – makes sense!) |
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Hypergeometric Distribution σx^2 |
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= n*A*(N-A) / N2 * {(N-n)/(N-1)} |
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You can use binomial to approximate the hypergeometric if the sample size is below what percent of the population |
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Negative Binomial Distribution |
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Determines the probability that the xth success occurs on the nth trial given a constant probability of success, p, where n = number of trials until x successes are observe |
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Negative Binomial Distribution μ |
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= x / p (if you are hoping for two successes and p = 0.5, then μ = 2/0.5 = 4; you would expect it to take 4 trials to achieve two successes |
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Negative Binomial Distribution σn^2 |
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A special case of the negative binomial distribution in which we want to find the probability that the first success occurs on the nth trial (x = 1) |
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Geometric Distribution μn |
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What is reverse of the binomial distribution |
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Where P(X=x) represents the probability of obtaining x successes per area of opportunity given a knowledge of the parameter λ. |
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the “expected” or average number of successes per area of opportunit |
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