Ln 1 = ?

Ln e = ?

ln e^x = ?

0

1

x

(tan x) ^2 = [(sec x)^2 - 1]

so Integral of [(sec x)^2 - 1]=

tanx - x

e^0=

d  cos^-1 x

_________________

dx

=

arc cos x

which = -1/(1-x^2)^1/2

-1

_________

(1-x^2)^1/2

d arcsin x

________________

dx

(derivative of... arc sin x is)

1

____________

(1-u^2)^1/2

d arctan u

__________________

du

d (tan u)^-1

________________

du

1

           ____________   du/dx

(1 + u^2)

1

_____________

x [(x^2 - 1)^1/2]

(sin x)^2 = (1/2) (1- cos 2x)

(cos x)^2 = (1/2) (1+ cos 2x)