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        (e^(x^A)) * Ax^(A-1) --------------- |  
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        (ln sqrt(x+A))'= ----------------- |  
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        How Do You Solve The Following: (-Ae^((Bx^C)+D))'  ---------------- |  
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        Take the Derivative of: (Bx^C)+D) Which Is CBx^C-1 ----------  Multiply the Derivative of (Bx^C)+D) by -A Which is -A(CBx^C-1) ---------------- Multiply the previous solution by  e^((Bx^C)+D) Which gives you... -A(CBx^C-1)e^((Bx^C)+D) ----------------- |  
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        ln((-Ax^B)+Cx)' = ---------------- |  
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        ((-BAx^B-1)+C)/((-Ax^B)+Cx) ---------------------------- |  
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        (ln [(Ax−B)((Cx^D)+E)])' ------------------------- |  
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        (A/(Ax-B))+((DCx^D-1)/((Cx^D)+E)) ------------------- |  
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        ((x^B)(e^(-Cx))' = ------------------- |  
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        e^(-Cx)((-Cx^B)+(Bx^B-1)) ------------- |  
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        ((x^A)ln|x|)'= ----------------- |  
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        (x^(A-1))(1+Aln|x|) ------------------ |  
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        (sqrt(lnAx))'= -------------- |  
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        1/2x(sqrt(lnAx)) -------------- |  
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        (((e^x)-A)/(ln|x|))'= ----------------- |  
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        ((xe^x)ln|x|-(e^x)+A)/(x(ln|x|)^2) ----------------- |  
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        (((e^Ax)-(e^-Ax))/x)'= ------------------------- |  
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        (Ax((e^Ax)-(e^-Ax))-((e^Ax)+(e^-Ax)))/(x)^2 ------------------- |  
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        ((ex^Ax+B)ln(Cx-D))'= ------------------- |  
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        ((Ce^Ax+B)/(Cx-D))+(Ae^Ax+B)ln(Cx-D) --------------------- |  
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        (ln(ln|Ax|))'= ----------------- |  
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